runSafe()
Execute the task without throwing errors, returning a Result type instead.
Syntax
typescript
task.runSafe(signal?: AbortSignal): Futurable<SafeResult<T>>Return Value
A Futurable that resolves to:
typescript
type SafeResult<T> =
| { success: true; data: T; error: null }
| { success: false; data: null; error: any };Examples
typescript
const result = await task.runSafe();
if (result.success) {
console.log('Data:', result.data);
} else {
console.error('Error:', result.error);
}With Early Return
typescript
async function fetchUser(id: number) {
const result = await FuturableTask
.fetch(`/api/users/${id}`)
.map(res => res.json())
.runSafe();
if (!result.success) {
console.error('Failed:', result.error);
return null;
}
return result.data;
}